Write a C program to modify the constant variable.

Q : Write a C program to modify the constant variable.

Solution : 

#include<stdio.h>

void main()

{

const int a=1;

int *p;

What is automatic type promotion in c

Q :  In the following declaration statement:

char c=’A’;
Variable c stores one byte of memory space while character constants ‘A’ stores one byte memory space. How one byte variables can stores two byte character constant? What is automatic type promotion in c?

Solution : 

Character constant reserve two byte of memory space to represent octal or hexadecimal character constant but char variable stores only its one byte ASCII value.

In C language, char type is used to store a 1 byte integer. When you assign 'A' to char c, you are not assigning the letter A itself into memory. Rather, you are assigning the number (integer) representing the A character. Each letter has a digit that represent it. . Remember that unlike humans, computers cannot understand letters. That's why we need a way to translate them into digits. To do this we use differnet coding styles like: ASCII, UTF-8, etc If your machine use ASCII coding then the value assigned to char c would be 65 (0x41 hex). As you may notice, 0x41 is one byte and can be stored in your char variable.

Automatic type promotion

Some data types like char , short int take less number of bytes than int, these data types are automatically promoted to int or unsigned int when an operation is performed on them. This is called integer promotion. For example no arithmetic calculation happens on smaller types like char, short and enum. They are first converted to int or unsigned int, and then arithmetic is done on them. If an int can represent all values of the original type, the value is converted to an int . Otherwise, it is converted to an unsigned int.

int main()

{

    char a = 30, b = 40, c = 10;

    char d = (a * b) / c;

    printf ("%d ", d);

    return 0;

}

At first look, the expression (a*b)/c seems to cause arithmetic overflow because signed characters can have values only from -128 to 127 (in most of the C compilers), and the value of subexpression ‘(a*b)’ is 1200 which is greater than 128. But integer promotion happens here in arithmetic done on char types and we get the appropriate result without any overflow.

Consider the following program as another example.

Next Question

Text File Input Through C Language

Q : Write a C program to write a line of string in a text file.

Solution : 

#include<stdio.h>

void main()

{

     FILE *pt;

     char ch[100],c;

     int i;

     pt=fopen("test.txt","w");

Gridview FIll VB.net

Dynamic fill data gridview using VB.net

Public Sub fill_gridview(ByRef dt As DataGridView, ByVal sql As String)

        Dim con As New OleDbConnection(getconstr)

        Dim da As New OleDbDataAdapter(sql, con)

        Dim ds As New DataSet

        Try