2d Array Compare

Q : Write a function that returns 1 if the two matrices passed to it as argument are equal and 0
otherwise.

Solution : 

#include<stdio.h>

#include<conio.h>

#define ROW 2

#define COL 2

int compare(int a1[ROW][COL],int a2[ROW][COL]);

void main()

{

     int ar1[ROW][COL],ar2[ROW][COL],r,c;

     clrscr();

     printf("\nFirst Array Input\n");

     for(r=0;r<ROW;r++)

     {

           for(c=0;c<COL;c++)

           {

                printf("Enter Number>> ");

                scanf("%d",&ar1[r][c]);

           }

     }

     printf("\nSecond Array Input\n");

     for(r=0;r<ROW;r++)

     {

           for(c=0;c<COL;c++)

           {

                printf("Enter Number>> ");

                scanf("%d",&ar2[r][c]);

           }

     }

     if(compare(ar1,ar2)==1)

           printf("\nIdentical");

     else

           printf("\nNot Identical");

     getch();

}

int compare(int a1[ROW][COL],int a2[ROW][COL])

{

     int r,c,flag=1;

     for(r=0;r<ROW;r++)

     {

           for(c=0;c<COL;c++)

           {

                if(a1[r][c]!=a2[r][c])

                {

                      flag=0;

                      break;

                }

           }

           if(flag==0)

                break;

     }

     if(r==ROW)

           return 1;

     else

           return 0;

}

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