Write a C program to find size of structure without using sizeof operator.

Q  : Write a C program to find size of structure without using sizeof operator.

#include<stdio.h>

#include<conio.h>

struct stu

{

     int roll;

     char name[20];

     float marks[3];

};

void main()

{

     struct stu *pt=NULL;

     clrscr();

     pt++;

     printf("\n\tSize of pointer is %d",pt);

     getch();

}

NULL means pointer is not point any location. So NULL will assign 0 in it.  Increment operator jump pointer some byte further which is equivalent to the size of pointer. This process is same as in array for address calculation.

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